3600t^2-60t=0

Solution for 3600t^2-60t=0 equation:

3600t^2-60t=0

a = 3600; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·3600·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*3600}=\frac{0}{7200}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*3600}=\frac{120}{7200}
=1/60
$